What are the solutions to the equation r^2=-96 ?

The solutions to the equation r^2=-96 are r=4sqrt(6)i,r=-4sqrt(6)i

Find the zeros of r^2=-96

The zeros of r^2=-96 are r=4sqrt(6)i,r=-4sqrt(6)i

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r^{2} = - 96

r = 46 i, r = - 46 i

Solution steps

r^{2} = - 96

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = - 96, r = - - 96

- 96 = 46 i

- - 96 = - 46 i

r = 46 i, r = - 46 i

x^{2} - 8 x + 65 = 0

x^{2} - 0.2 x - 4.85 = 0

x^{2} = \frac{2}{3} x + \frac{16}{3}

y, x^{2} + y^{2} + 2 x y - 7 x - 6 y + 10 = 0

(1 - x) (1 - x) + 4 = 0

What are the solutions to the equation r^2=-96 ?
The solutions to the equation r^2=-96 are r=4sqrt(6)i,r=-4sqrt(6)i
Find the zeros of r^2=-96
The zeros of r^2=-96 are r=4sqrt(6)i,r=-4sqrt(6)i