What are the solutions to the equation factor 2w^2-16w=12w-48 ?

The solutions to the equation factor 2w^2-16w=12w-48 are w=2,w=12

Find the zeros of factor 2w^2-16w=12w-48

The zeros of factor 2w^2-16w=12w-48 are w=2,w=12

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2 w^{2} - 16 w = 12 w - 48

w = 2, w = 12

Solution steps

2 w^{2} - 16 w = 12 w - 48

Move

48

to the left side

2 w^{2} - 16 w + 48 = 12 w

Move

12 w

to the left side

2 w^{2} - 28 w + 48 = 0

Factor

2 w^{2} - 28 w + 48 : 2 (w - 2) (w - 12)

2 (w - 2) (w - 12) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

w - 2 = 0 or w - 12 = 0

Solve

w - 2 = 0 : w = 2

Solve

w - 12 = 0 : w = 12

The solutions to the quadratic equation are:

w = 2, w = 12

3 x^{2} + 7 x - 3 = 3 x + 1

6 - 3 x^{2} = 3

9 x^{2} + 24 x + 15 = 0

b, m = 4 f b^{2} - g^{2}

(x + 3) \times (x - 5) = 0

What are the solutions to the equation factor 2w^2-16w=12w-48 ?
The solutions to the equation factor 2w^2-16w=12w-48 are w=2,w=12
Find the zeros of factor 2w^2-16w=12w-48
The zeros of factor 2w^2-16w=12w-48 are w=2,w=12