What are the solutions to the equation 9x^2+24x+15=0 ?

The solutions to the equation 9x^2+24x+15=0 are x=-1,x=-5/3

Find the zeros of 9x^2+24x+15=0

The zeros of 9x^2+24x+15=0 are x=-1,x=-5/3

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9 x^{2} + 24 x + 15 = 0

x = - 1, x = - \frac{5}{3}

Decimal

x = - 1, x = - 1.66666 \dots

Solution steps

9 x^{2} + 24 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 9 \cdot 15}{2 \cdot 9}

2 4^{2} - 4 \cdot 9 \cdot 15 = 6

x_{1, 2} = \frac{- 24 \pm 6}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 24 + 6}{2 \cdot 9}, x_{2} = \frac{- 24 - 6}{2 \cdot 9}

x = \frac{- 24 + 6}{2 \cdot 9} : - 1

x = \frac{- 24 - 6}{2 \cdot 9} : - \frac{5}{3}

The solutions to the quadratic equation are:

x = - 1, x = - \frac{5}{3}

b, m = 4 f b^{2} - g^{2}

(x + 3) \times (x - 5) = 0

x^{2} + 12 x + 13 = x + 3

y, y = (x - y)^{2}

4 x^{2} + 28 x = - 49

What are the solutions to the equation 9x^2+24x+15=0 ?
The solutions to the equation 9x^2+24x+15=0 are x=-1,x=-5/3
Find the zeros of 9x^2+24x+15=0
The zeros of 9x^2+24x+15=0 are x=-1,x=-5/3