What are the solutions to the equation 4x^2+28x=-49 ?

The solutions to the equation 4x^2+28x=-49 are x=-7/2

Find the zeros of 4x^2+28x=-49

The zeros of 4x^2+28x=-49 are x=-7/2

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4 x^{2} + 28 x = - 49

x = - \frac{7}{2}

Decimal Notation

x = - 3.5

Solution steps

4 x^{2} + 28 x = - 49

Move

49

to the left side

4 x^{2} + 28 x + 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 28 \pm 2 8 ^{2} - 4 \cdot 4 \cdot 49}{2 \cdot 4}

2 8^{2} - 4 \cdot 4 \cdot 49 = 0

x_{1, 2} = \frac{- 28 \pm 0}{2 \cdot 4}

x = \frac{- 28}{2 \cdot 4}

\frac{- 28}{2 \cdot 4} = - \frac{7}{2}

x = - \frac{7}{2}

The solution to the quadratic equation is:

x = - \frac{7}{2}

x^{2} + 27 = 12 x

2 n^{2} - 18 n + 40 = 0

- 3 x^{2} - 99 = - 42 x

y, x^{2} + y^{2} = 2 x y

u^{2} - 6 u + 1 = 0

What are the solutions to the equation 4x^2+28x=-49 ?
The solutions to the equation 4x^2+28x=-49 are x=-7/2
Find the zeros of 4x^2+28x=-49
The zeros of 4x^2+28x=-49 are x=-7/2