What are the solutions to the equation factor 2n^2-18n+40=0 ?

The solutions to the equation factor 2n^2-18n+40=0 are n=4,n=5

Find the zeros of factor 2n^2-18n+40=0

The zeros of factor 2n^2-18n+40=0 are n=4,n=5

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2 n^{2} - 18 n + 40 = 0

n = 4, n = 5

Solution steps

2 n^{2} - 18 n + 40 = 0

Factor

2 n^{2} - 18 n + 40 : 2 (n - 4) (n - 5)

2 (n - 4) (n - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

n - 4 = 0 or n - 5 = 0

Solve

n - 4 = 0 : n = 4

Solve

n - 5 = 0 : n = 5

The solutions to the quadratic equation are:

n = 4, n = 5

- 3 x^{2} - 99 = - 42 x

y, x^{2} + y^{2} = 2 x y

u^{2} - 6 u + 1 = 0

z^{2} - 3 z - 11 = - 6 z

- 75 x^{2} - 15 x - 100 = - 150 x^{2} + 10 x + 250

What are the solutions to the equation factor 2n^2-18n+40=0 ?
The solutions to the equation factor 2n^2-18n+40=0 are n=4,n=5
Find the zeros of factor 2n^2-18n+40=0
The zeros of factor 2n^2-18n+40=0 are n=4,n=5