What are the solutions to the equation (3z-15)^2+43=-2 ?

The solutions to the equation (3z-15)^2+43=-2 are z=sqrt(5)i+5,z=-sqrt(5)i+5

Find the zeros of (3z-15)^2+43=-2

The zeros of (3z-15)^2+43=-2 are z=sqrt(5)i+5,z=-sqrt(5)i+5

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(3 z - 15)^{2} + 43 = - 2

z = 5 i + 5, z = - 5 i + 5

Solution steps

(3 z - 15)^{2} + 43 = - 2

Move

43

to the right side

(3 z - 15)^{2} = - 45

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 z - 15 = - 45 : z = 5 i + 5

Solve

3 z - 15 = - - 45 : z = - 5 i + 5

The solutions to the quadratic equation are:

z = 5 i + 5, z = - 5 i + 5

2 x^{2} - 20 x + 46 = 0

8^{2} + x^{2} = 1 1^{2}

3 x^{2} - 26 x + 16 = 0

3 x^{2} + 6 x - 132 = 0

y, x^{2} - x y + y^{2} = 6

What are the solutions to the equation (3z-15)^2+43=-2 ?
The solutions to the equation (3z-15)^2+43=-2 are z=sqrt(5)i+5,z=-sqrt(5)i+5
Find the zeros of (3z-15)^2+43=-2
The zeros of (3z-15)^2+43=-2 are z=sqrt(5)i+5,z=-sqrt(5)i+5