What are the solutions to the equation 4x^2+13x=-13 ?

The solutions to the equation 4x^2+13x=-13 are x=-13/8+i(sqrt(39))/8 ,x=-13/8-i(sqrt(39))/8

Find the zeros of 4x^2+13x=-13

The zeros of 4x^2+13x=-13 are x=-13/8+i(sqrt(39))/8 ,x=-13/8-i(sqrt(39))/8

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4 x^{2} + 13 x = - 13

x = - \frac{13}{8} + i \frac{39}{8}, x = - \frac{13}{8} - i \frac{39}{8}

Solution steps

4 x^{2} + 13 x = - 13

Move

13

to the left side

4 x^{2} + 13 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 4 \cdot 13}{2 \cdot 4}

Simplify

1 3^{2} - 4 \cdot 4 \cdot 13 : 39 i

x_{1, 2} = \frac{- 13 \pm 39 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 13 + 39 i}{2 \cdot 4}, x_{2} = \frac{- 13 - 39 i}{2 \cdot 4}

x = \frac{- 13 + 39 i}{2 \cdot 4} : - \frac{13}{8} + i \frac{39}{8}

x = \frac{- 13 - 39 i}{2 \cdot 4} : - \frac{13}{8} - i \frac{39}{8}

The solutions to the quadratic equation are:

x = - \frac{13}{8} + i \frac{39}{8}, x = - \frac{13}{8} - i \frac{39}{8}

1 6^{2} + x^{2} = 3 2^{2}

6 n^{2} + 7 n - 11 = 5 n^{2}

3 y^{2} - 36 y - 47 = 0

2 x^{2} = - 98

(x) = - x^{2} - 2 x + 7

What are the solutions to the equation 4x^2+13x=-13 ?
The solutions to the equation 4x^2+13x=-13 are x=-13/8+i(sqrt(39))/8 ,x=-13/8-i(sqrt(39))/8
Find the zeros of 4x^2+13x=-13
The zeros of 4x^2+13x=-13 are x=-13/8+i(sqrt(39))/8 ,x=-13/8-i(sqrt(39))/8