What are the solutions to the equation 8w^2-8w+2=0 ?

The solutions to the equation 8w^2-8w+2=0 are w= 1/2

Find the zeros of 8w^2-8w+2=0

The zeros of 8w^2-8w+2=0 are w= 1/2

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8 w^{2} - 8 w + 2 = 0

w = \frac{1}{2}

Decimal Notation

w = 0.5

Solution steps

8 w^{2} - 8 w + 2 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 8 \cdot 2}{2 \cdot 8}

(- 8)^{2} - 4 \cdot 8 \cdot 2 = 0

w_{1, 2} = \frac{- ( - 8 ) \pm 0}{2 \cdot 8}

w = \frac{- ( - 8 )}{2 \cdot 8}

\frac{- ( - 8 )}{2 \cdot 8} = \frac{1}{2}

w = \frac{1}{2}

The solution to the quadratic equation is:

w = \frac{1}{2}

y, x^{2} + x y + 2 y^{2} = 1

413 = 9 x^{2} + 2 x + 1

y, 1 = 3 x + 2 x^{2} y^{2}

- 150 = \frac{1}{2} (- 0.98) x^{2}

8 x^{2} - 6 x = 0

What are the solutions to the equation 8w^2-8w+2=0 ?
The solutions to the equation 8w^2-8w+2=0 are w= 1/2
Find the zeros of 8w^2-8w+2=0
The zeros of 8w^2-8w+2=0 are w= 1/2