What are the solutions to the equation 0=4x^2+4x-14 ?

The solutions to the equation 0=4x^2+4x-14 are x=(-1+sqrt(15))/2 ,x=-(1+sqrt(15))/2

Find the zeros of 0=4x^2+4x-14

The zeros of 0=4x^2+4x-14 are x=(-1+sqrt(15))/2 ,x=-(1+sqrt(15))/2

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0 = 4 x^{2} + 4 x - 14

x = \frac{- 1 + 15}{2}, x = - \frac{1 + 15}{2}

Decimal Notation

x = 1.43649 \dots, x = - 2.43649 \dots

Solution steps

0 = 4 x^{2} + 4 x - 14

Switch sides

4 x^{2} + 4 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 ( - 14 )}{2 \cdot 4}

4^{2} - 4 \cdot 4 (- 14) = 415

x_{1, 2} = \frac{- 4 \pm 4 15}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 4 + 4 15}{2 \cdot 4}, x_{2} = \frac{- 4 - 4 15}{2 \cdot 4}

x = \frac{- 4 + 4 15}{2 \cdot 4} : \frac{- 1 + 15}{2}

x = \frac{- 4 - 4 15}{2 \cdot 4} : - \frac{1 + 15}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 15}{2}, x = - \frac{1 + 15}{2}

2 x^{2} + 20 x = - 3

2 x^{2} + 12 x + 3 = 15

12 x^{2} - 6 x + 10 = 0

x^{2} - 3 x + 8 = - 2

m, m = 3 n^{2} + 6 n - 25

What are the solutions to the equation 0=4x^2+4x-14 ?
The solutions to the equation 0=4x^2+4x-14 are x=(-1+sqrt(15))/2 ,x=-(1+sqrt(15))/2
Find the zeros of 0=4x^2+4x-14
The zeros of 0=4x^2+4x-14 are x=(-1+sqrt(15))/2 ,x=-(1+sqrt(15))/2