What are the solutions to the equation 2x^2+12x+3=15 ?

The solutions to the equation 2x^2+12x+3=15 are x=-3+sqrt(15),x=-3-sqrt(15)

Find the zeros of 2x^2+12x+3=15

The zeros of 2x^2+12x+3=15 are x=-3+sqrt(15),x=-3-sqrt(15)

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2 x^{2} + 12 x + 3 = 15

x = - 3 + 15, x = - 3 - 15

Decimal Notation

x = 0.87298 \dots, x = - 6.87298 \dots

Solution steps

2 x^{2} + 12 x + 3 = 15

Move

15

to the left side

2 x^{2} + 12 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 2 ( - 12 )}{2 \cdot 2}

1 2^{2} - 4 \cdot 2 (- 12) = 415

x_{1, 2} = \frac{- 12 \pm 4 15}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 12 + 4 15}{2 \cdot 2}, x_{2} = \frac{- 12 - 4 15}{2 \cdot 2}

x = \frac{- 12 + 4 15}{2 \cdot 2} : - 3 + 15

x = \frac{- 12 - 4 15}{2 \cdot 2} : - 3 - 15

The solutions to the quadratic equation are:

x = - 3 + 15, x = - 3 - 15

12 x^{2} - 6 x + 10 = 0

x^{2} - 3 x + 8 = - 2

m, m = 3 n^{2} + 6 n - 25

1 0^{2} + 5^{2} = x^{2}

8 - \frac{6}{5} = 7 - x - \frac{6}{5} x^{2} + 1

What are the solutions to the equation 2x^2+12x+3=15 ?
The solutions to the equation 2x^2+12x+3=15 are x=-3+sqrt(15),x=-3-sqrt(15)
Find the zeros of 2x^2+12x+3=15
The zeros of 2x^2+12x+3=15 are x=-3+sqrt(15),x=-3-sqrt(15)