What are the solutions to the equation 8-6/5 =7-x-6/5 x^2+1 ?

The solutions to the equation 8-6/5 =7-x-6/5 x^2+1 are x=-3/2 ,x= 2/3

Find the zeros of 8-6/5 =7-x-6/5 x^2+1

The zeros of 8-6/5 =7-x-6/5 x^2+1 are x=-3/2 ,x= 2/3

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8 - \frac{6}{5} = 7 - x - \frac{6}{5} x^{2} + 1

x = - \frac{3}{2}, x = \frac{2}{3}

Decimal Notation

x = - 1.5, x = 0.66666 \dots

Solution steps

8 - \frac{6}{5} = 7 - x - \frac{6}{5} x^{2} + 1

Multiply both sides by

5

40 - 6 = 35 - 5 x - 6 x^{2} + 5

34 = - 6 x^{2} - 5 x + 40

Switch sides

- 6 x^{2} - 5 x + 40 = 34

Move

34

to the left side

- 6 x^{2} - 5 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 6 ) \cdot 6}{2 ( - 6 )}

(- 5)^{2} - 4 (- 6) \cdot 6 = 13

x_{1, 2} = \frac{- ( - 5 ) \pm 13}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 13}{2 ( - 6 )}, x_{2} = \frac{- ( - 5 ) - 13}{2 ( - 6 )}

x = \frac{- ( - 5 ) + 13}{2 ( - 6 )} : - \frac{3}{2}

x = \frac{- ( - 5 ) - 13}{2 ( - 6 )} : \frac{2}{3}

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = \frac{2}{3}

5 x^{2} - 21 x + 11 = - 4 x

7 x^{2} + 28 x = - 2

4^{2} = 2.25 x^{2} + x^{2}

x^{2} - x - 12

- 5 (2 x - 20) (15 + 5 x) = 0

What are the solutions to the equation 8-6/5 =7-x-6/5 x^2+1 ?
The solutions to the equation 8-6/5 =7-x-6/5 x^2+1 are x=-3/2 ,x= 2/3
Find the zeros of 8-6/5 =7-x-6/5 x^2+1
The zeros of 8-6/5 =7-x-6/5 x^2+1 are x=-3/2 ,x= 2/3