What are the solutions to the equation 4^2=2.25x^2+x^2 ?

The solutions to the equation 4^2=2.25x^2+x^2 are x= 8/(sqrt(13)),x=-8/(sqrt(13))

Find the zeros of 4^2=2.25x^2+x^2

The zeros of 4^2=2.25x^2+x^2 are x= 8/(sqrt(13)),x=-8/(sqrt(13))

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4^{2} = 2.25 x^{2} + x^{2}

x = \frac{8}{13}, x = - \frac{8}{13}

Decimal Notation

x = 2.21880 \dots, x = - 2.21880 \dots

Solution steps

4^{2} = 2.25 x^{2} + x^{2}

Switch sides

2.25 x^{2} + x^{2} = 4^{2}

Add similar elements:

2.25 x^{2} + x^{2} = 3.25 x^{2}

3.25 x^{2} = 4^{2}

4^{2} = 16

3.25 x^{2} = 16

Multiply both sides by

100

325 x^{2} = 1600

Divide both sides by

325

x^{2} = \frac{64}{13}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{64}{13}, x = - \frac{64}{13}

\frac{64}{13} = \frac{8}{13}

- \frac{64}{13} = - \frac{8}{13}

x = \frac{8}{13}, x = - \frac{8}{13}

x^{2} - x - 12

- 5 (2 x - 20) (15 + 5 x) = 0

4 x^{2} - 2 x = - 5

x^{2} + 5 = 10

4 x^{2} - 16 x = - 16

What are the solutions to the equation 4^2=2.25x^2+x^2 ?
The solutions to the equation 4^2=2.25x^2+x^2 are x= 8/(sqrt(13)),x=-8/(sqrt(13))
Find the zeros of 4^2=2.25x^2+x^2
The zeros of 4^2=2.25x^2+x^2 are x= 8/(sqrt(13)),x=-8/(sqrt(13))