What are the solutions to the equation 7t^2-18t=14+10t ?

The solutions to the equation 7t^2-18t=14+10t are t=2+sqrt(6),t=2-sqrt(6)

Find the zeros of 7t^2-18t=14+10t

The zeros of 7t^2-18t=14+10t are t=2+sqrt(6),t=2-sqrt(6)

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7 t^{2} - 18 t = 14 + 10 t

t = 2 + 6, t = 2 - 6

Decimal Notation

t = 4.44948 \dots, t = - 0.44948 \dots

Solution steps

7 t^{2} - 18 t = 14 + 10 t

Move

10 t

to the left side

7 t^{2} - 28 t = 14

Move

14

to the left side

7 t^{2} - 28 t - 14 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 \cdot 7 ( - 14 )}{2 \cdot 7}

(- 28)^{2} - 4 \cdot 7 (- 14) = 146

t_{1, 2} = \frac{- ( - 28 ) \pm 14 6}{2 \cdot 7}

Separate the solutions

t_{1} = \frac{- ( - 28 ) + 14 6}{2 \cdot 7}, t_{2} = \frac{- ( - 28 ) - 14 6}{2 \cdot 7}

t = \frac{- ( - 28 ) + 14 6}{2 \cdot 7} : 2 + 6

t = \frac{- ( - 28 ) - 14 6}{2 \cdot 7} : 2 - 6

The solutions to the quadratic equation are:

t = 2 + 6, t = 2 - 6

3 x^{2} + 8 x - 3 = 0

6 x^{2} - 12 x + 9 = 0

3 x^{2} + 11 x - 15 = 0

7 q^{2} + 6 q + 3 = 6 q^{2}

x^{2} + 9 x + 35 = 0

What are the solutions to the equation 7t^2-18t=14+10t ?
The solutions to the equation 7t^2-18t=14+10t are t=2+sqrt(6),t=2-sqrt(6)
Find the zeros of 7t^2-18t=14+10t
The zeros of 7t^2-18t=14+10t are t=2+sqrt(6),t=2-sqrt(6)