What are the solutions to the equation 2m^2-5m+6=0 ?

The solutions to the equation 2m^2-5m+6=0 are m= 5/4+i(sqrt(23))/4 ,m= 5/4-i(sqrt(23))/4

Find the zeros of 2m^2-5m+6=0

The zeros of 2m^2-5m+6=0 are m= 5/4+i(sqrt(23))/4 ,m= 5/4-i(sqrt(23))/4

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2 m^{2} - 5 m + 6 = 0

m = \frac{5}{4} + i \frac{23}{4}, m = \frac{5}{4} - i \frac{23}{4}

Solution steps

2 m^{2} - 5 m + 6 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

Simplify

(- 5)^{2} - 4 \cdot 2 \cdot 6 : 23 i

m_{1, 2} = \frac{- ( - 5 ) \pm 23 i}{2 \cdot 2}

Separate the solutions

m_{1} = \frac{- ( - 5 ) + 23 i}{2 \cdot 2}, m_{2} = \frac{- ( - 5 ) - 23 i}{2 \cdot 2}

m = \frac{- ( - 5 ) + 23 i}{2 \cdot 2} : \frac{5}{4} + i \frac{23}{4}

m = \frac{- ( - 5 ) - 23 i}{2 \cdot 2} : \frac{5}{4} - i \frac{23}{4}

The solutions to the quadratic equation are:

m = \frac{5}{4} + i \frac{23}{4}, m = \frac{5}{4} - i \frac{23}{4}

2 x^{2} - 58 = 104

2 x^{2} = 4

s^{2} - 8 s - 20 = 0

25 x^{2} = 20 x - 4

14 x^{2} - 6 = 0

What are the solutions to the equation 2m^2-5m+6=0 ?
The solutions to the equation 2m^2-5m+6=0 are m= 5/4+i(sqrt(23))/4 ,m= 5/4-i(sqrt(23))/4
Find the zeros of 2m^2-5m+6=0
The zeros of 2m^2-5m+6=0 are m= 5/4+i(sqrt(23))/4 ,m= 5/4-i(sqrt(23))/4