What are the solutions to the equation factor 25x^2=20x-4 ?

The solutions to the equation factor 25x^2=20x-4 are x= 2/5

Find the zeros of factor 25x^2=20x-4

The zeros of factor 25x^2=20x-4 are x= 2/5

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25 x^{2} = 20 x - 4

x = \frac{2}{5}

Decimal Notation

x = 0.4

Solution steps

25 x^{2} = 20 x - 4

Move

4

to the left side

25 x^{2} + 4 = 20 x

Move

20 x

to the left side

25 x^{2} + 4 - 20 x = 0

Write in the standard form

a x^{2} + b x + c = 0

25 x^{2} - 20 x + 4 = 0

Factor

25 x^{2} - 20 x + 4 : (5 x - 2)^{2}

(5 x - 2)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 x - 2 = 0

Solve

5 x - 2 = 0 : x = \frac{2}{5}

The solution to the quadratic equation is:

x = \frac{2}{5}

14 x^{2} - 6 = 0

x^{2} - 10 x + 10 = - 5

x^{2} - 42 x + 8 = 0

x^{2} - 5 x - 31 = 5

y, x^{2} + 2 x y + y^{2} + x - y = 0

What are the solutions to the equation factor 25x^2=20x-4 ?
The solutions to the equation factor 25x^2=20x-4 are x= 2/5
Find the zeros of factor 25x^2=20x-4
The zeros of factor 25x^2=20x-4 are x= 2/5