What are the solutions to the equation x^2-10x+10=-5 ?

The solutions to the equation x^2-10x+10=-5 are x=5+sqrt(10),x=5-sqrt(10)

Find the zeros of x^2-10x+10=-5

The zeros of x^2-10x+10=-5 are x=5+sqrt(10),x=5-sqrt(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 10 x + 10 = - 5

x = 5 + 10, x = 5 - 10

Decimal Notation

x = 8.16227 \dots, x = 1.83772 \dots

Solution steps

x^{2} - 10 x + 10 = - 5

Move

5

to the left side

x^{2} - 10 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 15 = 210

x_{1, 2} = \frac{- ( - 10 ) \pm 2 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 10}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 10}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 10}{2 \cdot 1} : 5 + 10

x = \frac{- ( - 10 ) - 2 10}{2 \cdot 1} : 5 - 10

The solutions to the quadratic equation are:

x = 5 + 10, x = 5 - 10

x^{2} - 42 x + 8 = 0

x^{2} - 5 x - 31 = 5

y, x^{2} + 2 x y + y^{2} + x - y = 0

x = x^{2} - 5 x + 6

x^{2} + 6 x - 9.49 = 0

What are the solutions to the equation x^2-10x+10=-5 ?
The solutions to the equation x^2-10x+10=-5 are x=5+sqrt(10),x=5-sqrt(10)
Find the zeros of x^2-10x+10=-5
The zeros of x^2-10x+10=-5 are x=5+sqrt(10),x=5-sqrt(10)