What are the solutions to the equation x^2-4sqrt(2)x+8=0 ?

The solutions to the equation x^2-4sqrt(2)x+8=0 are x=2sqrt(2)

Find the zeros of x^2-4sqrt(2)x+8=0

The zeros of x^2-4sqrt(2)x+8=0 are x=2sqrt(2)

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x^{2} - 42 x + 8 = 0

x = 22

Decimal Notation

x = 2.82842 \dots

Solution steps

x^{2} - 42 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 2 ) \pm ( - 4 2 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

(- 42)^{2} - 4 \cdot 1 \cdot 8 = 0

x_{1, 2} = \frac{- ( - 4 2 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 4 2 )}{2 \cdot 1}

\frac{- ( - 4 2 )}{2 \cdot 1} = 22

x = 22

The solution to the quadratic equation is:

x = 22

x^{2} - 5 x - 31 = 5

y, x^{2} + 2 x y + y^{2} + x - y = 0

x = x^{2} - 5 x + 6

x^{2} + 6 x - 9.49 = 0

6 x^{2} - 24 x - 4 = 0

What are the solutions to the equation x^2-4sqrt(2)x+8=0 ?
The solutions to the equation x^2-4sqrt(2)x+8=0 are x=2sqrt(2)
Find the zeros of x^2-4sqrt(2)x+8=0
The zeros of x^2-4sqrt(2)x+8=0 are x=2sqrt(2)