What are the solutions to the equation 6x^2-24x-4=0 ?

The solutions to the equation 6x^2-24x-4=0 are x=(6+sqrt(42))/3 ,x=(6-sqrt(42))/3

Find the zeros of 6x^2-24x-4=0

The zeros of 6x^2-24x-4=0 are x=(6+sqrt(42))/3 ,x=(6-sqrt(42))/3

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6 x^{2} - 24 x - 4 = 0

x = \frac{6 + 42}{3}, x = \frac{6 - 42}{3}

Decimal Notation

x = 4.16024 \dots, x = - 0.16024 \dots

Solution steps

6 x^{2} - 24 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 6 ( - 4 )}{2 \cdot 6}

(- 24)^{2} - 4 \cdot 6 (- 4) = 442

x_{1, 2} = \frac{- ( - 24 ) \pm 4 42}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 4 42}{2 \cdot 6}, x_{2} = \frac{- ( - 24 ) - 4 42}{2 \cdot 6}

x = \frac{- ( - 24 ) + 4 42}{2 \cdot 6} : \frac{6 + 42}{3}

x = \frac{- ( - 24 ) - 4 42}{2 \cdot 6} : \frac{6 - 42}{3}

The solutions to the quadratic equation are:

x = \frac{6 + 42}{3}, x = \frac{6 - 42}{3}

0 = x^{2} - 13 x

6 x^{2} + 600 = 0

x^{2} + 2 x

2 (x + 6)^{2} - 41 = - 21

5 - x^{2} = \frac{1}{4} x^{2}

What are the solutions to the equation 6x^2-24x-4=0 ?
The solutions to the equation 6x^2-24x-4=0 are x=(6+sqrt(42))/3 ,x=(6-sqrt(42))/3
Find the zeros of 6x^2-24x-4=0
The zeros of 6x^2-24x-4=0 are x=(6+sqrt(42))/3 ,x=(6-sqrt(42))/3