What are the solutions to the equation u^2+3u+2=0 ?

The solutions to the equation u^2+3u+2=0 are u=-1,u=-2

Find the zeros of u^2+3u+2=0

The zeros of u^2+3u+2=0 are u=-1,u=-2

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u^{2} + 3 u + 2 = 0

u = - 1, u = - 2

Solution steps

u^{2} + 3 u + 2 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot 2 = 1

u_{1, 2} = \frac{- 3 \pm 1}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- 3 + 1}{2 \cdot 1}, u_{2} = \frac{- 3 - 1}{2 \cdot 1}

u = \frac{- 3 + 1}{2 \cdot 1} : - 1

u = \frac{- 3 - 1}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

u = - 1, u = - 2

x^{2} + 9 x = 0

72 = 2 π + r^{2}

x, 2 x^{2} + 2 y^{2} z^{2} - 5 yz x = 0

2 x^{2} - 12 x + 28

x^{2} + 4 x = 7 x + 4

What are the solutions to the equation u^2+3u+2=0 ?
The solutions to the equation u^2+3u+2=0 are u=-1,u=-2
Find the zeros of u^2+3u+2=0
The zeros of u^2+3u+2=0 are u=-1,u=-2