What are the solutions to the equation 72=2pi+r^2 ?

The solutions to the equation 72=2pi+r^2 are r=sqrt(72-2pi),r=-sqrt(72-2pi)

Find the zeros of 72=2pi+r^2

The zeros of 72=2pi+r^2 are r=sqrt(72-2pi),r=-sqrt(72-2pi)

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72 = 2 π + r^{2}

r = 72 - 2 π, r = - 72 - 2 π

Decimal Notation

r = 8.10659 \dots, r = - 8.10659 \dots

Solution steps

72 = 2 π + r^{2}

Switch sides

2 π + r^{2} = 72

Move

2 π

to the right side

r^{2} = 72 - 2 π

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = 72 - 2 π, r = - 72 - 2 π

x, 2 x^{2} + 2 y^{2} z^{2} - 5 yz x = 0

2 x^{2} - 12 x + 28

x^{2} + 4 x = 7 x + 4

k^{2} - 3 k - 10 = 0

a^{2} + 5 a + 25 = 0

What are the solutions to the equation 72=2pi+r^2 ?
The solutions to the equation 72=2pi+r^2 are r=sqrt(72-2pi),r=-sqrt(72-2pi)
Find the zeros of 72=2pi+r^2
The zeros of 72=2pi+r^2 are r=sqrt(72-2pi),r=-sqrt(72-2pi)