What are the solutions to the equation 60^2-42^2=x^2 ?

The solutions to the equation 60^2-42^2=x^2 are x=6sqrt(51),x=-6sqrt(51)

Find the zeros of 60^2-42^2=x^2

The zeros of 60^2-42^2=x^2 are x=6sqrt(51),x=-6sqrt(51)

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6 0^{2} - 4 2^{2} = x^{2}

x = 651, x = - 651

Decimal Notation

x = 42.84857 \dots, x = - 42.84857 \dots

Solution steps

6 0^{2} - 4 2^{2} = x^{2}

Switch sides

x^{2} = 6 0^{2} - 4 2^{2}

Simplify

6 0^{2} - 4 2^{2} : 1836

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1836, x = - 1836

1836 = 651

- 1836 = - 651

x = 651, x = - 651

3 r^{2} + 4 r + 5 = 0

0 = 9 x^{2} + 3 x - 2

x^{2} + 8 x + 41

x^{2} + x + \frac{1}{3} = \frac{2}{3}

12 x = 100 x^{2} - 2 \times 9.8 \times 5

What are the solutions to the equation 60^2-42^2=x^2 ?
The solutions to the equation 60^2-42^2=x^2 are x=6sqrt(51),x=-6sqrt(51)
Find the zeros of 60^2-42^2=x^2
The zeros of 60^2-42^2=x^2 are x=6sqrt(51),x=-6sqrt(51)