What are the solutions to the equation -8x^2+3=0 ?

The solutions to the equation -8x^2+3=0 are x=(sqrt(3))/(2sqrt(2)),x=-(sqrt(3))/(2sqrt(2))

Find the zeros of -8x^2+3=0

The zeros of -8x^2+3=0 are x=(sqrt(3))/(2sqrt(2)),x=-(sqrt(3))/(2sqrt(2))

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- 8 x^{2} + 3 = 0

x = \frac{3}{2 2}, x = - \frac{3}{2 2}

Decimal Notation

x = 0.61237 \dots, x = - 0.61237 \dots

Solution steps

- 8 x^{2} + 3 = 0

Move

3

to the right side

- 8 x^{2} = - 3

Divide both sides by

- 8

x^{2} = \frac{3}{8}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{3}{8}, x = - \frac{3}{8}

\frac{3}{8} = \frac{3}{2 2}

- \frac{3}{8} = - \frac{3}{2 2}

x = \frac{3}{2 2}, x = - \frac{3}{2 2}

x^{2} - 24 x = - 22 x + 24 - x^{2}

x^{2} - 8 x - 1

4 p^{2} - 1 = - 2

\frac{x ^{2}}{81} - 6 = - 2

m^{2} = 0.09

What are the solutions to the equation -8x^2+3=0 ?
The solutions to the equation -8x^2+3=0 are x=(sqrt(3))/(2sqrt(2)),x=-(sqrt(3))/(2sqrt(2))
Find the zeros of -8x^2+3=0
The zeros of -8x^2+3=0 are x=(sqrt(3))/(2sqrt(2)),x=-(sqrt(3))/(2sqrt(2))