What are the solutions to the equation 3p^2=-8p-5 ?

The solutions to the equation 3p^2=-8p-5 are p=-1,p=-5/3

Find the zeros of 3p^2=-8p-5

The zeros of 3p^2=-8p-5 are p=-1,p=-5/3

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3 p^{2} = - 8 p - 5

p = - 1, p = - \frac{5}{3}

Decimal Notation

p = - 1, p = - 1.66666 \dots

Solution steps

3 p^{2} = - 8 p - 5

Move

5

to the left side

3 p^{2} + 5 = - 8 p

Move

8 p

to the left side

3 p^{2} + 5 + 8 p = 0

Write in the standard form

a x^{2} + b x + c = 0

3 p^{2} + 8 p + 5 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

8^{2} - 4 \cdot 3 \cdot 5 = 2

p_{1, 2} = \frac{- 8 \pm 2}{2 \cdot 3}

Separate the solutions

p_{1} = \frac{- 8 + 2}{2 \cdot 3}, p_{2} = \frac{- 8 - 2}{2 \cdot 3}

p = \frac{- 8 + 2}{2 \cdot 3} : - 1

p = \frac{- 8 - 2}{2 \cdot 3} : - \frac{5}{3}

The solutions to the quadratic equation are:

p = - 1, p = - \frac{5}{3}

y, x^{2} + 6 x y + 12 y^{2} = 28

2 y^{2} - y + 1 = 0

2 x^{2} + 5 x - 3

3 x^{2} - 2 x + 6

2 (3 x + 9)^{2} = 50

What are the solutions to the equation 3p^2=-8p-5 ?
The solutions to the equation 3p^2=-8p-5 are p=-1,p=-5/3
Find the zeros of 3p^2=-8p-5
The zeros of 3p^2=-8p-5 are p=-1,p=-5/3