What are the solutions to the equation 25(5x-3)^2+6=22 ?

The solutions to the equation 25(5x-3)^2+6=22 are x= 19/25 ,x= 11/25

Find the zeros of 25(5x-3)^2+6=22

The zeros of 25(5x-3)^2+6=22 are x= 19/25 ,x= 11/25

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25 (5 x - 3)^{2} + 6 = 22

x = \frac{19}{25}, x = \frac{11}{25}

Decimal Notation

x = 0.76, x = 0.44

Solution steps

25 (5 x - 3)^{2} + 6 = 22

Move

6

to the right side

25 (5 x - 3)^{2} = 16

Divide both sides by

25

(5 x - 3)^{2} = \frac{16}{25}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x - 3 = \frac{16}{25} : x = \frac{19}{25}

Solve

5 x - 3 = - \frac{16}{25} : x = \frac{11}{25}

The solutions to the quadratic equation are:

x = \frac{19}{25}, x = \frac{11}{25}

0.7 t^{2} = 14 t

x, m x^{2} + 5 x + 2 = 0

4 x^{2} + 83 = - 36 x

8 x^{2} - 40 x + 32 = 0

8 x^{2} + 14 x - 9 = 6

What are the solutions to the equation 25(5x-3)^2+6=22 ?
The solutions to the equation 25(5x-3)^2+6=22 are x= 19/25 ,x= 11/25
Find the zeros of 25(5x-3)^2+6=22
The zeros of 25(5x-3)^2+6=22 are x= 19/25 ,x= 11/25