What are the solutions to the equation 8x^2-40x+32=0 ?

The solutions to the equation 8x^2-40x+32=0 are x=4,x=1

Find the zeros of 8x^2-40x+32=0

The zeros of 8x^2-40x+32=0 are x=4,x=1

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8 x^{2} - 40 x + 32 = 0

x = 4, x = 1

Solution steps

8 x^{2} - 40 x + 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 8 \cdot 32}{2 \cdot 8}

(- 40)^{2} - 4 \cdot 8 \cdot 32 = 24

x_{1, 2} = \frac{- ( - 40 ) \pm 24}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 40 ) + 24}{2 \cdot 8}, x_{2} = \frac{- ( - 40 ) - 24}{2 \cdot 8}

x = \frac{- ( - 40 ) + 24}{2 \cdot 8} : 4

x = \frac{- ( - 40 ) - 24}{2 \cdot 8} : 1

The solutions to the quadratic equation are:

x = 4, x = 1

8 x^{2} + 14 x - 9 = 6

- 300 = 17 t - 4.9 t^{2}

3 p^{2} - 13 p + 4 = - 4

(x) (x + 1) = 240

2 x^{2} - x - 11 = - 3

What are the solutions to the equation 8x^2-40x+32=0 ?
The solutions to the equation 8x^2-40x+32=0 are x=4,x=1
Find the zeros of 8x^2-40x+32=0
The zeros of 8x^2-40x+32=0 are x=4,x=1