What are the solutions to the equation 2x^2-x-11=-3 ?

The solutions to the equation 2x^2-x-11=-3 are x=(1+sqrt(65))/4 ,x=(1-sqrt(65))/4

Find the zeros of 2x^2-x-11=-3

The zeros of 2x^2-x-11=-3 are x=(1+sqrt(65))/4 ,x=(1-sqrt(65))/4

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2 x^{2} - x - 11 = - 3

x = \frac{1 + 65}{4}, x = \frac{1 - 65}{4}

Decimal Notation

x = 2.26556 \dots, x = - 1.76556 \dots

Solution steps

2 x^{2} - x - 11 = - 3

Move

3

to the left side

2 x^{2} - x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 8 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 8) = 65

x_{1, 2} = \frac{- ( - 1 ) \pm 65}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 65}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 65}{2 \cdot 2}

x = \frac{- ( - 1 ) + 65}{2 \cdot 2} : \frac{1 + 65}{4}

x = \frac{- ( - 1 ) - 65}{2 \cdot 2} : \frac{1 - 65}{4}

The solutions to the quadratic equation are:

x = \frac{1 + 65}{4}, x = \frac{1 - 65}{4}

5 x^{2} + 5 x - \frac{3}{4} = 0

3 x^{2} + 12 x = 7 x + 2

(x - 1)^{2}

s^{2} - 6 s + 25

x^{2} - 18 x + 60 = - 21

What are the solutions to the equation 2x^2-x-11=-3 ?
The solutions to the equation 2x^2-x-11=-3 are x=(1+sqrt(65))/4 ,x=(1-sqrt(65))/4
Find the zeros of 2x^2-x-11=-3
The zeros of 2x^2-x-11=-3 are x=(1+sqrt(65))/4 ,x=(1-sqrt(65))/4