What are the solutions to the equation x^2-18x+60=-21 ?

The solutions to the equation x^2-18x+60=-21 are x=9

Find the zeros of x^2-18x+60=-21

The zeros of x^2-18x+60=-21 are x=9

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x^{2} - 18 x + 60 = - 21

x = 9

Solution steps

x^{2} - 18 x + 60 = - 21

Move

21

to the left side

x^{2} - 18 x + 81 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 81}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 81 = 0

x_{1, 2} = \frac{- ( - 18 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 18 )}{2 \cdot 1}

\frac{- ( - 18 )}{2 \cdot 1} = 9

x = 9

The solution to the quadratic equation is:

x = 9

9 x^{2} - 48 x + 65 = 0

2 W^{2} - 5 W - 52 = 0

6 x^{2} - 90 x + 300 = 0

4 (x - 6)^{2} = - 32

9 (x^{2} - 6) + 17 = 12

What are the solutions to the equation x^2-18x+60=-21 ?
The solutions to the equation x^2-18x+60=-21 are x=9
Find the zeros of x^2-18x+60=-21
The zeros of x^2-18x+60=-21 are x=9