What are the solutions to the equation 2W^2-5W-52=0 ?

The solutions to the equation 2W^2-5W-52=0 are W= 13/2 ,W=-4

Find the zeros of 2W^2-5W-52=0

The zeros of 2W^2-5W-52=0 are W= 13/2 ,W=-4

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2 W^{2} - 5 W - 52 = 0

W = \frac{13}{2}, W = - 4

Decimal Notation

W = 6.5, W = - 4

Solution steps

2 W^{2} - 5 W - 52 = 0

Solve with the quadratic formula

W_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 52 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 52) = 21

W_{1, 2} = \frac{- ( - 5 ) \pm 21}{2 \cdot 2}

Separate the solutions

W_{1} = \frac{- ( - 5 ) + 21}{2 \cdot 2}, W_{2} = \frac{- ( - 5 ) - 21}{2 \cdot 2}

W = \frac{- ( - 5 ) + 21}{2 \cdot 2} : \frac{13}{2}

W = \frac{- ( - 5 ) - 21}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

W = \frac{13}{2}, W = - 4

6 x^{2} - 90 x + 300 = 0

4 (x - 6)^{2} = - 32

9 (x^{2} - 6) + 17 = 12

- 3 x^{2} - 8 = 0

16 x^{2} - 49 = 0

What are the solutions to the equation 2W^2-5W-52=0 ?
The solutions to the equation 2W^2-5W-52=0 are W= 13/2 ,W=-4
Find the zeros of 2W^2-5W-52=0
The zeros of 2W^2-5W-52=0 are W= 13/2 ,W=-4