What are the solutions to the equation x^2-4x+125=0 ?

The solutions to the equation x^2-4x+125=0 are x=2+11i,x=2-11i

Find the zeros of x^2-4x+125=0

The zeros of x^2-4x+125=0 are x=2+11i,x=2-11i

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x^{2} - 4 x + 125 = 0

x = 2 + 11 i, x = 2 - 11 i

Solution steps

x^{2} - 4 x + 125 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 125}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 125 : 22 i

x_{1, 2} = \frac{- ( - 4 ) \pm 22 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 22 i}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 22 i}{2 \cdot 1}

x = \frac{- ( - 4 ) + 22 i}{2 \cdot 1} : 2 + 11 i

x = \frac{- ( - 4 ) - 22 i}{2 \cdot 1} : 2 - 11 i

The solutions to the quadratic equation are:

x = 2 + 11 i, x = 2 - 11 i

10 w^{2} - 15 w - 9 = 18 - 6 w + 4 w^{2}

3 x^{2} - 2 = - x

y, x y + 2 x + 3 x^{2} = 4

- 2 x^{2} - 4 x + 6

3 t^{2} - 16 t + 5 = 0

What are the solutions to the equation x^2-4x+125=0 ?
The solutions to the equation x^2-4x+125=0 are x=2+11i,x=2-11i
Find the zeros of x^2-4x+125=0
The zeros of x^2-4x+125=0 are x=2+11i,x=2-11i