What are the solutions to the equation roots x^2+3x+9 ?

The solutions to the equation roots x^2+3x+9 are x=-3/2+i(3sqrt(3))/2 ,x=-3/2-i(3sqrt(3))/2

Find the zeros of roots x^2+3x+9

The zeros of roots x^2+3x+9 are x=-3/2+i(3sqrt(3))/2 ,x=-3/2-i(3sqrt(3))/2

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roots

x^{2} + 3 x + 9

x = - \frac{3}{2} + i \frac{3 3}{2}, x = - \frac{3}{2} - i \frac{3 3}{2}

Solution steps

x^{2} + 3 x + 9

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 3 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

Simplify

3^{2} - 4 \cdot 1 \cdot 9 : 33 i

x_{1, 2} = \frac{- 3 \pm 3 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 3 3 i}{2 \cdot 1}, x_{2} = \frac{- 3 - 3 3 i}{2 \cdot 1}

x = \frac{- 3 + 3 3 i}{2 \cdot 1} : - \frac{3}{2} + i \frac{3 3}{2}

x = \frac{- 3 - 3 3 i}{2 \cdot 1} : - \frac{3}{2} - i \frac{3 3}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{2} + i \frac{3 3}{2}, x = - \frac{3}{2} - i \frac{3 3}{2}

- 16 = x^{2} - 10 x

0 = 3 x^{2} + 4 x - 4

x^{2} + x a + a^{2}

- x^{2} - 0 x + 16 = 0

2 p^{2} + 2 p - 84 = 0

What are the solutions to the equation roots x^2+3x+9 ?
The solutions to the equation roots x^2+3x+9 are x=-3/2+i(3sqrt(3))/2 ,x=-3/2-i(3sqrt(3))/2
Find the zeros of roots x^2+3x+9
The zeros of roots x^2+3x+9 are x=-3/2+i(3sqrt(3))/2 ,x=-3/2-i(3sqrt(3))/2