What are the solutions to the equation 2x^2-1x-120=0 ?

The solutions to the equation 2x^2-1x-120=0 are x=8,x=-15/2

Find the zeros of 2x^2-1x-120=0

The zeros of 2x^2-1x-120=0 are x=8,x=-15/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 1 x - 120 = 0

x = 8, x = - \frac{15}{2}

Decimal Notation

x = 8, x = - 7.5

Solution steps

2 x^{2} - 1 \cdot x - 120 = 0

Refine

2 x^{2} - x - 120 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 120 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 120) = 31

x_{1, 2} = \frac{- ( - 1 ) \pm 31}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 31}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 31}{2 \cdot 2}

x = \frac{- ( - 1 ) + 31}{2 \cdot 2} : 8

x = \frac{- ( - 1 ) - 31}{2 \cdot 2} : - \frac{15}{2}

The solutions to the quadratic equation are:

x = 8, x = - \frac{15}{2}

k, 2 k (k - 4) = 1

x^{2} + 3 x - 1000 = 0

x^{2} + 16 x + 128 = 0

4 (3 x + 8)^{2} + 17 = 21

y, 2 (x^{2} + y^{2}) = 25 (x^{2} - y^{2})

What are the solutions to the equation 2x^2-1x-120=0 ?
The solutions to the equation 2x^2-1x-120=0 are x=8,x=-15/2
Find the zeros of 2x^2-1x-120=0
The zeros of 2x^2-1x-120=0 are x=8,x=-15/2