What are the solutions to the equation 0=-x^2-4x-4 ?

The solutions to the equation 0=-x^2-4x-4 are x=-2

Find the zeros of 0=-x^2-4x-4

The zeros of 0=-x^2-4x-4 are x=-2

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0 = - x^{2} - 4 x - 4

x = - 2

Solution steps

0 = - x^{2} - 4 x - 4

Switch sides

- x^{2} - 4 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 1 ) ( - 4 )}{2 ( - 1 )}

(- 4)^{2} - 4 (- 1) (- 4) = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 ( - 1 )}

x = \frac{- ( - 4 )}{2 ( - 1 )}

\frac{- ( - 4 )}{2 ( - 1 )} = - 2

x = - 2

The solution to the quadratic equation is:

x = - 2

- 9 x^{2} - 6 x - 5 = 0

2 q^{2} + 10 q - 9 = 0

x^{2} - 20 x + 90 = 0

2 y^{2} - 3 y - 9 = 0

x^{2} - 14 x - 11 = - 30

What are the solutions to the equation 0=-x^2-4x-4 ?
The solutions to the equation 0=-x^2-4x-4 are x=-2
Find the zeros of 0=-x^2-4x-4
The zeros of 0=-x^2-4x-4 are x=-2