What are the solutions to the equation 8p^2+8p-5=0 ?

The solutions to the equation 8p^2+8p-5=0 are p=(-2+sqrt(14))/4 ,p=-(2+sqrt(14))/4

Find the zeros of 8p^2+8p-5=0

The zeros of 8p^2+8p-5=0 are p=(-2+sqrt(14))/4 ,p=-(2+sqrt(14))/4

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8 p^{2} + 8 p - 5 = 0

p = \frac{- 2 + 14}{4}, p = - \frac{2 + 14}{4}

Decimal Notation

p = 0.43541 \dots, p = - 1.43541 \dots

Solution steps

8 p^{2} + 8 p - 5 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 8 ( - 5 )}{2 \cdot 8}

8^{2} - 4 \cdot 8 (- 5) = 414

p_{1, 2} = \frac{- 8 \pm 4 14}{2 \cdot 8}

Separate the solutions

p_{1} = \frac{- 8 + 4 14}{2 \cdot 8}, p_{2} = \frac{- 8 - 4 14}{2 \cdot 8}

p = \frac{- 8 + 4 14}{2 \cdot 8} : \frac{- 2 + 14}{4}

p = \frac{- 8 - 4 14}{2 \cdot 8} : - \frac{2 + 14}{4}

The solutions to the quadratic equation are:

p = \frac{- 2 + 14}{4}, p = - \frac{2 + 14}{4}

- 2 x^{2} + 4 x + 6 = 15

x^{2} + 3 x = a x + 3 a

y, 3 x^{2} + 8 x y + 9 y^{2} = 6

5 a^{2} - 100 = 0

2 x^{2} + 192 = 40 x

What are the solutions to the equation 8p^2+8p-5=0 ?
The solutions to the equation 8p^2+8p-5=0 are p=(-2+sqrt(14))/4 ,p=-(2+sqrt(14))/4
Find the zeros of 8p^2+8p-5=0
The zeros of 8p^2+8p-5=0 are p=(-2+sqrt(14))/4 ,p=-(2+sqrt(14))/4