What are the solutions to the equation 3^3+2n^2=36 ?

The solutions to the equation 3^3+2n^2=36 are n= 3/(sqrt(2)),n=-3/(sqrt(2))

Find the zeros of 3^3+2n^2=36

The zeros of 3^3+2n^2=36 are n= 3/(sqrt(2)),n=-3/(sqrt(2))

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3^{3} + 2 n^{2} = 36

n = \frac{3}{2}, n = - \frac{3}{2}

Decimal Notation

n = 2.12132 \dots, n = - 2.12132 \dots

Solution steps

3^{3} + 2 n^{2} = 36

Move

3^{3}

to the right side

2 n^{2} = 9

Divide both sides by

2

n^{2} = \frac{9}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = \frac{9}{2}, n = - \frac{9}{2}

\frac{9}{2} = \frac{3}{2}

- \frac{9}{2} = - \frac{3}{2}

n = \frac{3}{2}, n = - \frac{3}{2}

3 x^{2} = - 5 x - 3

x^{2} - 3 x + 6 + 8 = 0

x^{2} + x - 5 = - x^{2} - 5

1 - 6 x (1 - x) = 0

2 k^{2} + 11 k + 12 = 0

What are the solutions to the equation 3^3+2n^2=36 ?
The solutions to the equation 3^3+2n^2=36 are n= 3/(sqrt(2)),n=-3/(sqrt(2))
Find the zeros of 3^3+2n^2=36
The zeros of 3^3+2n^2=36 are n= 3/(sqrt(2)),n=-3/(sqrt(2))