What are the solutions to the equation 2k^2+11k+12=0 ?

The solutions to the equation 2k^2+11k+12=0 are k=-3/2 ,k=-4

Find the zeros of 2k^2+11k+12=0

The zeros of 2k^2+11k+12=0 are k=-3/2 ,k=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 k^{2} + 11 k + 12 = 0

k = - \frac{3}{2}, k = - 4

Decimal Notation

k = - 1.5, k = - 4

Solution steps

2 k^{2} + 11 k + 12 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 2 \cdot 12}{2 \cdot 2}

1 1^{2} - 4 \cdot 2 \cdot 12 = 5

k_{1, 2} = \frac{- 11 \pm 5}{2 \cdot 2}

Separate the solutions

k_{1} = \frac{- 11 + 5}{2 \cdot 2}, k_{2} = \frac{- 11 - 5}{2 \cdot 2}

k = \frac{- 11 + 5}{2 \cdot 2} : - \frac{3}{2}

k = \frac{- 11 - 5}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

k = - \frac{3}{2}, k = - 4

8 x^{2} - 10 = 3 x^{2} + 3

\frac{3}{4} (x + 3)^{2} = - 96

y, x^{2} + 4 x y + y^{2} = 0

y, 2 x^{2} = y^{2}

4 x^{2} + 1 = 8 x - 2

What are the solutions to the equation 2k^2+11k+12=0 ?
The solutions to the equation 2k^2+11k+12=0 are k=-3/2 ,k=-4
Find the zeros of 2k^2+11k+12=0
The zeros of 2k^2+11k+12=0 are k=-3/2 ,k=-4