What are the solutions to the equation 3/4 (x+3)^2=-96 ?

The solutions to the equation 3/4 (x+3)^2=-96 are x=8sqrt(2)i-3,x=-8sqrt(2)i-3

Find the zeros of 3/4 (x+3)^2=-96

The zeros of 3/4 (x+3)^2=-96 are x=8sqrt(2)i-3,x=-8sqrt(2)i-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{3}{4} (x + 3)^{2} = - 96

x = 82 i - 3, x = - 82 i - 3

Solution steps

\frac{3}{4} (x + 3)^{2} = - 96

Multiply both sides by

4

3 (x + 3)^{2} = - 384

Divide both sides by

3

(x + 3)^{2} = - 128

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = - 128 : x = 82 i - 3

Solve

x + 3 = - - 128 : x = - 82 i - 3

The solutions to the quadratic equation are:

x = 82 i - 3, x = - 82 i - 3

y, x^{2} + 4 x y + y^{2} = 0

y, 2 x^{2} = y^{2}

4 x^{2} + 1 = 8 x - 2

x, x^{2} + 2 y^{2} + 3 z^{2} = 1

x^{2} = - 44

What are the solutions to the equation 3/4 (x+3)^2=-96 ?
The solutions to the equation 3/4 (x+3)^2=-96 are x=8sqrt(2)i-3,x=-8sqrt(2)i-3
Find the zeros of 3/4 (x+3)^2=-96
The zeros of 3/4 (x+3)^2=-96 are x=8sqrt(2)i-3,x=-8sqrt(2)i-3