What are the solutions to the equation factor 4x^2+1=8x-2 ?

The solutions to the equation factor 4x^2+1=8x-2 are x= 1/2 ,x= 3/2

Find the zeros of factor 4x^2+1=8x-2

The zeros of factor 4x^2+1=8x-2 are x= 1/2 ,x= 3/2

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4 x^{2} + 1 = 8 x - 2

x = \frac{1}{2}, x = \frac{3}{2}

Decimal Notation

x = 0.5, x = 1.5

Solution steps

4 x^{2} + 1 = 8 x - 2

Move

2

to the left side

4 x^{2} + 3 = 8 x

Move

8 x

to the left side

4 x^{2} + 3 - 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 8 x + 3 = 0

Factor

4 x^{2} - 8 x + 3 : (2 x - 1) (2 x - 3)

(2 x - 1) (2 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 1 = 0 or 2 x - 3 = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

2 x - 3 = 0 : x = \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = \frac{3}{2}

x, x^{2} + 2 y^{2} + 3 z^{2} = 1

x^{2} = - 44

16.1 x^{2} + 4.398 x - 2.661 = 0

x (x + 5) + 2 (x + 6) = 0

13 y^{2} - 48 y + 570 = 0

What are the solutions to the equation factor 4x^2+1=8x-2 ?
The solutions to the equation factor 4x^2+1=8x-2 are x= 1/2 ,x= 3/2
Find the zeros of factor 4x^2+1=8x-2
The zeros of factor 4x^2+1=8x-2 are x= 1/2 ,x= 3/2