What are the solutions to the equation x(x+5)+2(x+6)=0 ?

The solutions to the equation x(x+5)+2(x+6)=0 are x=-3,x=-4

Find the zeros of x(x+5)+2(x+6)=0

The zeros of x(x+5)+2(x+6)=0 are x=-3,x=-4

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x (x + 5) + 2 (x + 6) = 0

x = - 3, x = - 4

Solution steps

x (x + 5) + 2 (x + 6) = 0

Expand

x (x + 5) + 2 (x + 6) : x^{2} + 7 x + 12

x^{2} + 7 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 12 = 1

x_{1, 2} = \frac{- 7 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 1}{2 \cdot 1}, x_{2} = \frac{- 7 - 1}{2 \cdot 1}

x = \frac{- 7 + 1}{2 \cdot 1} : - 3

x = \frac{- 7 - 1}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = - 3, x = - 4

13 y^{2} - 48 y + 570 = 0

3 x^{2} - 6 x = 0

x^{2} - x

3 x^{2} - 2 x - 1 = 3 x + 1

5 n^{2} - 16 n + 11 = n^{2}

What are the solutions to the equation x(x+5)+2(x+6)=0 ?
The solutions to the equation x(x+5)+2(x+6)=0 are x=-3,x=-4
Find the zeros of x(x+5)+2(x+6)=0
The zeros of x(x+5)+2(x+6)=0 are x=-3,x=-4