What are the solutions to the equation 5n^2-16n+11=n^2 ?

The solutions to the equation 5n^2-16n+11=n^2 are n=(4+sqrt(5))/2 ,n=(4-sqrt(5))/2

Find the zeros of 5n^2-16n+11=n^2

The zeros of 5n^2-16n+11=n^2 are n=(4+sqrt(5))/2 ,n=(4-sqrt(5))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 n^{2} - 16 n + 11 = n^{2}

n = \frac{4 + 5}{2}, n = \frac{4 - 5}{2}

Decimal Notation

n = 3.11803 \dots, n = 0.88196 \dots

Solution steps

5 n^{2} - 16 n + 11 = n^{2}

Move

n^{2}

to the left side

4 n^{2} - 16 n + 11 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 4 \cdot 11}{2 \cdot 4}

(- 16)^{2} - 4 \cdot 4 \cdot 11 = 45

n_{1, 2} = \frac{- ( - 16 ) \pm 4 5}{2 \cdot 4}

Separate the solutions

n_{1} = \frac{- ( - 16 ) + 4 5}{2 \cdot 4}, n_{2} = \frac{- ( - 16 ) - 4 5}{2 \cdot 4}

n = \frac{- ( - 16 ) + 4 5}{2 \cdot 4} : \frac{4 + 5}{2}

n = \frac{- ( - 16 ) - 4 5}{2 \cdot 4} : \frac{4 - 5}{2}

The solutions to the quadratic equation are:

n = \frac{4 + 5}{2}, n = \frac{4 - 5}{2}

x^{2} + 5 x + 1 = 5 x + 2

3 = \frac{π d ^{2}}{4}

x^{2} = 162

s^{2} + 1.2 s + 1 = 0

4 x^{2} + 16 = - 144

What are the solutions to the equation 5n^2-16n+11=n^2 ?
The solutions to the equation 5n^2-16n+11=n^2 are n=(4+sqrt(5))/2 ,n=(4-sqrt(5))/2
Find the zeros of 5n^2-16n+11=n^2
The zeros of 5n^2-16n+11=n^2 are n=(4+sqrt(5))/2 ,n=(4-sqrt(5))/2