What are the solutions to the equation factor x^2+5x+1=5x+2 ?

The solutions to the equation factor x^2+5x+1=5x+2 are x=-1,x=1

Find the zeros of factor x^2+5x+1=5x+2

The zeros of factor x^2+5x+1=5x+2 are x=-1,x=1

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x^{2} + 5 x + 1 = 5 x + 2

x = - 1, x = 1

Solution steps

x^{2} + 5 x + 1 = 5 x + 2

Move

2

to the left side

x^{2} + 5 x - 1 = 5 x

Move

5 x

to the left side

x^{2} - 1 = 0

Factor

x^{2} - 1 : (x + 1) (x - 1)

(x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 1 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions to the quadratic equation are:

x = - 1, x = 1

3 = \frac{π d ^{2}}{4}

x^{2} = 162

s^{2} + 1.2 s + 1 = 0

4 x^{2} + 16 = - 144

x^{2} + 7 x = - 3

What are the solutions to the equation factor x^2+5x+1=5x+2 ?
The solutions to the equation factor x^2+5x+1=5x+2 are x=-1,x=1
Find the zeros of factor x^2+5x+1=5x+2
The zeros of factor x^2+5x+1=5x+2 are x=-1,x=1