What are the solutions to the equation 42x^2+11x-20=0 ?

The solutions to the equation 42x^2+11x-20=0 are x= 4/7 ,x=-5/6

Find the zeros of 42x^2+11x-20=0

The zeros of 42x^2+11x-20=0 are x= 4/7 ,x=-5/6

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42 x^{2} + 11 x - 20 = 0

x = \frac{4}{7}, x = - \frac{5}{6}

Decimal Notation

x = 0.57142 \dots, x = - 0.83333 \dots

Solution steps

42 x^{2} + 11 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 42 ( - 20 )}{2 \cdot 42}

1 1^{2} - 4 \cdot 42 (- 20) = 59

x_{1, 2} = \frac{- 11 \pm 59}{2 \cdot 42}

Separate the solutions

x_{1} = \frac{- 11 + 59}{2 \cdot 42}, x_{2} = \frac{- 11 - 59}{2 \cdot 42}

x = \frac{- 11 + 59}{2 \cdot 42} : \frac{4}{7}

x = \frac{- 11 - 59}{2 \cdot 42} : - \frac{5}{6}

The solutions to the quadratic equation are:

x = \frac{4}{7}, x = - \frac{5}{6}

x, (x - a)^{2} + y^{2} = a^{2}

16.1 x^{2} + 18 x = 50

x^{2} n^{3} + x^{2} m^{3} + m^{5} n^{4}

(2 x + 2)^{2} + 5 = 1

y, x^{2} + x y - y^{2} = 0

What are the solutions to the equation 42x^2+11x-20=0 ?
The solutions to the equation 42x^2+11x-20=0 are x= 4/7 ,x=-5/6
Find the zeros of 42x^2+11x-20=0
The zeros of 42x^2+11x-20=0 are x= 4/7 ,x=-5/6