What are the solutions to the equation -4x^2-40x=164 ?

The solutions to the equation -4x^2-40x=164 are x=-5-4i,x=-5+4i

Find the zeros of -4x^2-40x=164

The zeros of -4x^2-40x=164 are x=-5-4i,x=-5+4i

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- 4 x^{2} - 40 x = 164

x = - 5 - 4 i, x = - 5 + 4 i

Solution steps

- 4 x^{2} - 40 x = 164

Move

164

to the left side

- 4 x^{2} - 40 x - 164 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 ( - 4 ) ( - 164 )}{2 ( - 4 )}

Simplify

(- 40)^{2} - 4 (- 4) (- 164) : 32 i

x_{1, 2} = \frac{- ( - 40 ) \pm 32 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 40 ) + 32 i}{2 ( - 4 )}, x_{2} = \frac{- ( - 40 ) - 32 i}{2 ( - 4 )}

x = \frac{- ( - 40 ) + 32 i}{2 ( - 4 )} : - 5 - 4 i

x = \frac{- ( - 40 ) - 32 i}{2 ( - 4 )} : - 5 + 4 i

The solutions to the quadratic equation are:

x = - 5 - 4 i, x = - 5 + 4 i

- 4 x^{2} - 12 x - 5 = 0

- 5 x^{2} + x + 3 = 0

y, 3 x^{2} + 2 x + 5 y^{2} - 7 y + 23 = 0

x^{2} + 2 x - 25 = 20 - 2 x

1 0^{2} + 3^{2} = x^{2}

What are the solutions to the equation -4x^2-40x=164 ?
The solutions to the equation -4x^2-40x=164 are x=-5-4i,x=-5+4i
Find the zeros of -4x^2-40x=164
The zeros of -4x^2-40x=164 are x=-5-4i,x=-5+4i