What are the solutions to the equation -5x^2+x+3=0 ?

The solutions to the equation -5x^2+x+3=0 are x=-(-1+sqrt(61))/(10),x=(1+sqrt(61))/(10)

Find the zeros of -5x^2+x+3=0

The zeros of -5x^2+x+3=0 are x=-(-1+sqrt(61))/(10),x=(1+sqrt(61))/(10)

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- 5 x^{2} + x + 3 = 0

x = - \frac{- 1 + 61}{10}, x = \frac{1 + 61}{10}

Decimal Notation

x = - 0.68102 \dots, x = 0.88102 \dots

Solution steps

- 5 x^{2} + x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 5 ) \cdot 3}{2 ( - 5 )}

1^{2} - 4 (- 5) \cdot 3 = 61

x_{1, 2} = \frac{- 1 \pm 61}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 1 + 61}{2 ( - 5 )}, x_{2} = \frac{- 1 - 61}{2 ( - 5 )}

x = \frac{- 1 + 61}{2 ( - 5 )} : - \frac{- 1 + 61}{10}

x = \frac{- 1 - 61}{2 ( - 5 )} : \frac{1 + 61}{10}

The solutions to the quadratic equation are:

x = - \frac{- 1 + 61}{10}, x = \frac{1 + 61}{10}

y, 3 x^{2} + 2 x + 5 y^{2} - 7 y + 23 = 0

x^{2} + 2 x - 25 = 20 - 2 x

1 0^{2} + 3^{2} = x^{2}

16 (2 x - 1)^{2} = 25

z^{2} + \frac{25}{16} = 0

What are the solutions to the equation -5x^2+x+3=0 ?
The solutions to the equation -5x^2+x+3=0 are x=-(-1+sqrt(61))/(10),x=(1+sqrt(61))/(10)
Find the zeros of -5x^2+x+3=0
The zeros of -5x^2+x+3=0 are x=-(-1+sqrt(61))/(10),x=(1+sqrt(61))/(10)