What are the solutions to the equation 16(2x-1)^2=25 ?

The solutions to the equation 16(2x-1)^2=25 are x= 9/8 ,x=-1/8

Find the zeros of 16(2x-1)^2=25

The zeros of 16(2x-1)^2=25 are x= 9/8 ,x=-1/8

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16 (2 x - 1)^{2} = 25

x = \frac{9}{8}, x = - \frac{1}{8}

Decimal Notation

x = 1.125, x = - 0.125

Solution steps

16 (2 x - 1)^{2} = 25

Divide both sides by

16

(2 x - 1)^{2} = \frac{25}{16}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 1 = \frac{25}{16} : x = \frac{9}{8}

Solve

2 x - 1 = - \frac{25}{16} : x = - \frac{1}{8}

The solutions to the quadratic equation are:

x = \frac{9}{8}, x = - \frac{1}{8}

z^{2} + \frac{25}{16} = 0

16 t^{2} - 7 t = 17 t - 9

x^{2} - 30 = - x

2 x^{2} = - 7 x + 5

10 x^{2} + x - 21 = 0

What are the solutions to the equation 16(2x-1)^2=25 ?
The solutions to the equation 16(2x-1)^2=25 are x= 9/8 ,x=-1/8
Find the zeros of 16(2x-1)^2=25
The zeros of 16(2x-1)^2=25 are x= 9/8 ,x=-1/8