What are the solutions to the equation (x+1)^2=-48 ?

The solutions to the equation (x+1)^2=-48 are x=4sqrt(3)i-1,x=-4sqrt(3)i-1

Find the zeros of (x+1)^2=-48

The zeros of (x+1)^2=-48 are x=4sqrt(3)i-1,x=-4sqrt(3)i-1

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(x + 1)^{2} = - 48

x = 43 i - 1, x = - 43 i - 1

Solution steps

(x + 1)^{2} = - 48

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = - 48 : x = 43 i - 1

Solve

x + 1 = - - 48 : x = - 43 i - 1

The solutions to the quadratic equation are:

x = 43 i - 1, x = - 43 i - 1

\frac{7}{4} x^{2} + 4 x + 5 = 0

3 (3 x - 2) = (x - 4) (4 - x)

3 (3 x - 1)^{2} + 34 = 46

3 x^{2} + 1 = - 25 x - 7

x, a^{2} x^{2} + (a y - a) x = 2 + 2 y

What are the solutions to the equation (x+1)^2=-48 ?
The solutions to the equation (x+1)^2=-48 are x=4sqrt(3)i-1,x=-4sqrt(3)i-1
Find the zeros of (x+1)^2=-48
The zeros of (x+1)^2=-48 are x=4sqrt(3)i-1,x=-4sqrt(3)i-1