What are the solutions to the equation roots r^2-2r+5 ?

The solutions to the equation roots r^2-2r+5 are r=1+2i,r=1-2i

Find the zeros of roots r^2-2r+5

The zeros of roots r^2-2r+5 are r=1+2i,r=1-2i

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roots

r^{2} - 2 r + 5

r = 1 + 2 i, r = 1 - 2 i

Solution steps

r^{2} - 2 r + 5

The roots are the intercepts with the x-axis

(y = 0)

r^{2} - 2 r + 5 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 5 : 4 i

r_{1, 2} = \frac{- ( - 2 ) \pm 4 i}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 2 ) + 4 i}{2 \cdot 1}, r_{2} = \frac{- ( - 2 ) - 4 i}{2 \cdot 1}

r = \frac{- ( - 2 ) + 4 i}{2 \cdot 1} : 1 + 2 i

r = \frac{- ( - 2 ) - 4 i}{2 \cdot 1} : 1 - 2 i

The solutions to the quadratic equation are:

r = 1 + 2 i, r = 1 - 2 i

6 x^{2} + 7 x + 5 = 0

3 x^{2} + 12 x = 0

x^{2} + 7 x - 10 = - 2 x

10 x^{2} + 1000 = 0

1 0^{2} + 2 6^{2} = x^{2}

What are the solutions to the equation roots r^2-2r+5 ?
The solutions to the equation roots r^2-2r+5 are r=1+2i,r=1-2i
Find the zeros of roots r^2-2r+5
The zeros of roots r^2-2r+5 are r=1+2i,r=1-2i