What are the solutions to the equation 10^2+26^2=x^2 ?

The solutions to the equation 10^2+26^2=x^2 are x=2sqrt(194),x=-2sqrt(194)

Find the zeros of 10^2+26^2=x^2

The zeros of 10^2+26^2=x^2 are x=2sqrt(194),x=-2sqrt(194)

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1 0^{2} + 2 6^{2} = x^{2}

x = 2194, x = - 2194

Decimal Notation

x = 27.85677 \dots, x = - 27.85677 \dots

Solution steps

1 0^{2} + 2 6^{2} = x^{2}

Switch sides

x^{2} = 1 0^{2} + 2 6^{2}

Simplify

1 0^{2} + 2 6^{2} : 776

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 776, x = - 776

776 = 2194

- 776 = - 2194

x = 2194, x = - 2194

(x + 1) (x + 5) = 0

4 x^{2} + 10 x + 5 = 0

x^{2} + x - 0 = 0

- 2 (x + 4)^{2} + 3 = 0

4 (x - 5)^{2} = 12

What are the solutions to the equation 10^2+26^2=x^2 ?
The solutions to the equation 10^2+26^2=x^2 are x=2sqrt(194),x=-2sqrt(194)
Find the zeros of 10^2+26^2=x^2
The zeros of 10^2+26^2=x^2 are x=2sqrt(194),x=-2sqrt(194)