What are the solutions to the equation -2(x+4)^2+3=0 ?

The solutions to the equation -2(x+4)^2+3=0 are x=sqrt(3/2)-4,x=-sqrt(3/2)-4

Find the zeros of -2(x+4)^2+3=0

The zeros of -2(x+4)^2+3=0 are x=sqrt(3/2)-4,x=-sqrt(3/2)-4

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- 2 (x + 4)^{2} + 3 = 0

x = \frac{3}{2} - 4, x = - \frac{3}{2} - 4

Decimal Notation

x = - 2.77525 \dots, x = - 5.22474 \dots

Solution steps

- 2 (x + 4)^{2} + 3 = 0

Move

3

to the right side

- 2 (x + 4)^{2} = - 3

Divide both sides by

- 2

(x + 4)^{2} = \frac{3}{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = \frac{3}{2} : x = \frac{3}{2} - 4

Solve

x + 4 = - \frac{3}{2} : x = - \frac{3}{2} - 4

The solutions to the quadratic equation are:

x = \frac{3}{2} - 4, x = - \frac{3}{2} - 4

4 (x - 5)^{2} = 12

8 p^{2} + 8 p - 4 = 3 p^{2}

2 x^{2} = 5 + 3 x

2 x^{2} = x^{2} + 81

n^{2} + 1 = - 10

What are the solutions to the equation -2(x+4)^2+3=0 ?
The solutions to the equation -2(x+4)^2+3=0 are x=sqrt(3/2)-4,x=-sqrt(3/2)-4
Find the zeros of -2(x+4)^2+3=0
The zeros of -2(x+4)^2+3=0 are x=sqrt(3/2)-4,x=-sqrt(3/2)-4