What are the solutions to the equation roots 4s^2+s+1 ?

The solutions to the equation roots 4s^2+s+1 are s=-1/8+i(sqrt(15))/8 ,s=-1/8-i(sqrt(15))/8

Find the zeros of roots 4s^2+s+1

The zeros of roots 4s^2+s+1 are s=-1/8+i(sqrt(15))/8 ,s=-1/8-i(sqrt(15))/8

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roots

4 s^{2} + s + 1

s = - \frac{1}{8} + i \frac{15}{8}, s = - \frac{1}{8} - i \frac{15}{8}

Solution steps

4 s^{2} + s + 1

The roots are the intercepts with the x-axis

(y = 0)

4 s^{2} + s + 1 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

Simplify

1^{2} - 4 \cdot 4 \cdot 1 : 15 i

s_{1, 2} = \frac{- 1 \pm 15 i}{2 \cdot 4}

Separate the solutions

s_{1} = \frac{- 1 + 15 i}{2 \cdot 4}, s_{2} = \frac{- 1 - 15 i}{2 \cdot 4}

s = \frac{- 1 + 15 i}{2 \cdot 4} : - \frac{1}{8} + i \frac{15}{8}

s = \frac{- 1 - 15 i}{2 \cdot 4} : - \frac{1}{8} - i \frac{15}{8}

The solutions to the quadratic equation are:

s = - \frac{1}{8} + i \frac{15}{8}, s = - \frac{1}{8} - i \frac{15}{8}

3 x^{2} + 25 x + 8 = 0

x^{2} + 2 x = - 2 x - 5

3 y - y^{2} - 4 = 0

s^{2} + 14 s + 2 = 0

6 x^{2} + x - 5 = 0

What are the solutions to the equation roots 4s^2+s+1 ?
The solutions to the equation roots 4s^2+s+1 are s=-1/8+i(sqrt(15))/8 ,s=-1/8-i(sqrt(15))/8
Find the zeros of roots 4s^2+s+1
The zeros of roots 4s^2+s+1 are s=-1/8+i(sqrt(15))/8 ,s=-1/8-i(sqrt(15))/8