What are the solutions to the equation quadraticformula 6x^2+x-5=0 ?

The solutions to the equation quadraticformula 6x^2+x-5=0 are x= 5/6 ,x=-1

Find the zeros of quadraticformula 6x^2+x-5=0

The zeros of quadraticformula 6x^2+x-5=0 are x= 5/6 ,x=-1

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6 x^{2} + x - 5 = 0

x = \frac{5}{6}, x = - 1

Decimal Notation

x = 0.83333 \dots, x = - 1

Solution steps

6 x^{2} + x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 6 ( - 5 )}{2 \cdot 6}

1^{2} - 4 \cdot 6 (- 5) = 11

x_{1, 2} = \frac{- 1 \pm 11}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 1 + 11}{2 \cdot 6}, x_{2} = \frac{- 1 - 11}{2 \cdot 6}

x = \frac{- 1 + 11}{2 \cdot 6} : \frac{5}{6}

x = \frac{- 1 - 11}{2 \cdot 6} : - 1

The solutions to the quadratic equation are:

x = \frac{5}{6}, x = - 1

- x - x^{2} = 0

x^{2} + 4 x = 12

6 x^{2} - 35 = 11 x

y, 4 x^{2} - y^{2} = 0

a^{2} + 9 = 9

What are the solutions to the equation quadraticformula 6x^2+x-5=0 ?
The solutions to the equation quadraticformula 6x^2+x-5=0 are x= 5/6 ,x=-1
Find the zeros of quadraticformula 6x^2+x-5=0
The zeros of quadraticformula 6x^2+x-5=0 are x= 5/6 ,x=-1